(1/4)x^2+(1/2)x+(1/4)=0

Solution for (1/4)x^2+(1/2)x+(1/4)=0 equation:

(1/4)x^2+(1/2)x+(1/4)=0


Domain of the equation: 4)x^2!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/4)x^2+(+1/2)x+(+1/4)=0

We multiply parentheses

x^2+(+1/4)x^2+(+1/4)=0

We get rid of parentheses

x^2+(+1/4)x^2+1/4=0

We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$